F(x)=40x^2

Solution for F(x)=40x^2 equation:

(F)=40F^2

We move all terms to the left:

(F)-(40F^2)=0

determiningTheFunctionDomain
-40F^2+F=0

a = -40; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-40)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-40}=\frac{-2}{-80}
=1/40
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-40}=\frac{0}{-80}
=0
$